$$\frac{15}{8}m-11 = \frac{7}{4}m+1$$

$$ \begin{aligned} \frac{15}{8}m-11 &= \frac{7}{4}m+1&& \text{multiply ALL terms by } \color{blue}{ 8 }. \\[1 em]8 \cdot \frac{15}{8}m-8\cdot11 &= 8 \cdot \frac{7}{4}m+8\cdot1&& \text{cancel out the denominators} \\[1 em]15m-88 &= 14m+8&& \text{move the $ \color{blue}{ 14m } $ to the left side and $ \color{blue}{ -88 }$ to the right} \\[1 em]15m-14m &= 8+88&& \text{simplify left and right hand side} \\[1 em]m &= 96&& \\[1 em]m &= 96&& \\[1 em] \end{aligned} $$

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