$$ \begin{aligned} \frac{15}{x+3} &= 3&& \text{multiply ALL terms by } \color{blue}{ x+3 }. \\[1 em](x+3)\cdot\frac{15}{x+3} &= (x+3)\cdot3&& \text{cancel out the denominators} \\[1 em]15 &= 3x+9&& \text{ swap the left and right side of the equation } \\[1 em]3x+9 &= 15&& \text{ move 9 to the right } \\[1 em]3x &= 15-9&& \\[1 em]3x &= 6&& \text{ divide both sides by $ 3 $ } \\[1 em]x &= \frac{6}{3}&& \\[1 em]x &= 2&& \\[1 em] \end{aligned} $$
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