$$10-2(8-3)^2+\frac{24}{6} = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} 10-2(8-3)^2+\frac{24}{6} &= 0&& \text{multiply ALL terms by } \color{blue}{ 6 }. \\[1 em]6\cdot10-6\cdot2(8-3)^2+6\cdot\frac{24}{6} &= 6\cdot0&& \text{cancel out the denominators} \\[1 em]60-300+24 &= 0&& \text{simplify left side} \\[1 em]-216 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ -216 = 0 } $ is FALSE, we conclude that the equation has no solution.
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