$$1-\frac{3}{x} = \frac{10}{x^2}$$
Answer
$$ \begin{matrix}x_1 = 2 & x_2 = -1.52596 & x_3 = -0.23702+1.79456i \\[1 em] x_4 = -0.23702-1.79456i & \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 1-\frac{3}{x} &= \frac{10}{x^2}&& \text{multiply ALL terms by } \color{blue}{ xx^2 }. \\[1 em]xx^2\cdot1-xx^2\cdot\frac{3}{x} &= xx^2\cdot\frac{10}{x^2}&& \text{cancel out the denominators} \\[1 em]x^3-3 &= \frac{10}{x^1}&& \text{multiply ALL terms by } \color{blue}{ x^1 }. \\[1 em]x^1\cdot1x^3-x^1\cdot3 &= x^1\cdot\frac{10}{x^1}&& \text{cancel out the denominators} \\[1 em]x^4-3x &= 10&& \text{move all terms to the left hand side } \\[1 em]x^4-3x-10 &= 0&& \\[1 em] \end{aligned} $$
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