$$\frac{1}{4}-x = \frac{x}{8}$$

$$ \begin{aligned} \frac{1}{4}-x &= \frac{x}{8}&& \text{multiply ALL terms by } \color{blue}{ 8 }. \\[1 em]8\cdot\frac{1}{4}-8x &= 8 \cdot \frac{x}{8}&& \text{cancel out the denominators} \\[1 em]2-8x &= x&& \text{move the $ \color{blue}{ x } $ to the left side and $ \color{blue}{ 2 }$ to the right} \\[1 em]-8x-x &= -2&& \text{simplify left side} \\[1 em]-9x &= -2&& \text{ divide both sides by $ -9 $ } \\[1 em]x &= \frac{-2}{-9}&& \\[1 em]x &= \frac{2}{9}&& \\[1 em] \end{aligned} $$

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