$$ \begin{aligned} 1\cdot\frac{3}{5}+1\cdot\frac{2}{7}+1\cdot\frac{1}{4} &= 0&& \text{multiply ALL terms by } \color{blue}{ 140 }. \\[1 em]140\cdot1\cdot\frac{3}{5}+140\cdot1\cdot\frac{2}{7}+140\cdot1\cdot\frac{1}{4} &= 140\cdot0&& \text{cancel out the denominators} \\[1 em]84+40+35 &= 0&& \text{simplify left side} \\[1 em]159 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ 159 = 0 } $ is FALSE, we conclude that the equation has no solution.
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