$$0 = 12x^2-48x+36$$
Answer
$$ \begin{matrix}x_1 = 1 & x_2 = 3 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} 0 &= 12x^2-48x+36&& \text{move all terms to the left hand side } \\[1 em]0-12x^2+48x-36 &= 0&& \text{simplify left side} \\[1 em]-12x^2+48x-36 &= 0&& \\[1 em] \end{aligned} $$
$ -12x^{2}+48x-36 = 0 $ is a quadratic equation.
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