$$-145 \cdot \frac{x^2}{64}+\frac{81}{4} = 0$$
Answer
$$ \begin{matrix}x_1 = -36 \dfrac{\sqrt{ 145 }}{ 145 } & x_2 = \dfrac{ 36 \sqrt{ 145}}{ 145 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} -145 \cdot \frac{x^2}{64}+\frac{81}{4} &= 0&& \text{multiply ALL terms by } \color{blue}{ 64 }. \\[1 em]-64\cdot145 \cdot \frac{x^2}{64}+64\cdot\frac{81}{4} &= 64\cdot0&& \text{cancel out the denominators} \\[1 em]-145x^2+1296 &= 0&& \\[1 em] \end{aligned} $$
$ -145x^{2}+1296 = 0 $ is a quadratic equation.
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