$- 145 \cdot \frac{x ^{2}}{64} + \frac{81}{4} = 0$

Answer

$x_{1} = - 36 \frac{145}{145} x_{2} = \frac{36 145}{145}$

Explanation

- 145 \cdot \frac{x ^{2}}{64} + \frac{81}{4} - 64 \cdot 145 \cdot \frac{x ^{2}}{64} + 64 \cdot \frac{81}{4} - 145 x^{2} + 1296 = 0 = 64 \cdot 0 = 0 multiply ALL terms by 64 . cancel out the denominators

$- 145 x^{2} + 1296 = 0$ is a quadratic equation.

You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.

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−145⋅64x2​+481​=0

x1​=−36145145​​​x2​=14536145​​​

$- 145 \cdot \frac{x ^{2}}{64} + \frac{81}{4} = 0$

$x_{1} = - 36 \frac{145}{145} x_{2} = \frac{36 145}{145}$