$- 1 (x - 4) x = 0$

Answer

$x_{1} = 0 x_{2} = 4$

Explanation

- 1 (x - 4) x - (x - 4) x - (x^{2} - 4 x) - x^{2} + 4 x = 0 = 0 = 0 = 0 simplify left side

In order to solve $- x^{2} + 4 x = 0$ , first we need to factor our $x$ .

- x^{2} + 4 x = x (- x + 4)

$x = 0$ is a root of multiplicity $1$ .

The second root can be found by solving equation $- x + 4 = 0$ .

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−1(x−4)x=0

x1​=0​x2​=4​

$- 1 (x - 4) x = 0$

$x_{1} = 0 x_{2} = 4$