$$3\cdot(4-x)\cdot9 = 0$$
Answer
$$ x = 4 $$
Explanation
$$ \begin{aligned} 3\cdot(4-x)\cdot9 &= 0&& \text{simplify left side} \\[1 em](12-3x)\cdot9 &= 0&& \\[1 em]108-27x &= 0&& \\[1 em]-27x+108 &= 0&& \text{ move the constants to the right } \\[1 em]-27x &= -108&& \text{ divide both sides by $ -27 $ } \\[1 em]x &= \frac{-108}{-27}&& \\[1 em]x &= 4&& \\[1 em] \end{aligned} $$
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