$(3 x - 1) (2 x + 4) = 0$

Answer

$x_{1} = \frac{1}{3} x_{2} = - 2$

Explanation

(3 x - 1) (2 x + 4) 6 x^{2} + 12 x - 2 x - 4 6 x^{2} + 10 x - 4 = 0 = 0 = 0 simplify left side

$6 x^{2} + 10 x - 4 = 0$ is a quadratic equation.

You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.

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(3x−1)(2x+4)=0

x1​=31​​x2​=−2​

$(3 x - 1) (2 x + 4) = 0$

$x_{1} = \frac{1}{3} x_{2} = - 2$