$$(x+7)^2 = 5$$
Answer
$$ \begin{matrix}x_1 = -7-\sqrt{ 5 } & x_2 = -7+\sqrt{ 5 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x+7)^2 &= 5&& \text{simplify left side} \\[1 em]x^2+14x+49 &= 5&& \text{move all terms to the left hand side } \\[1 em]x^2+14x+49-5 &= 0&& \text{simplify left side} \\[1 em]x^2+14x+44 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+14x+44 = 0 $ is a quadratic equation.
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