$$(x+5)(x-3) = 0$$
Answer
$$ \begin{matrix}x_1 = 3 & x_2 = -5 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x+5)(x-3) &= 0&& \text{simplify left side} \\[1 em]x^2-3x+5x-15 &= 0&& \\[1 em]x^2+2x-15 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+2x-15 = 0 $ is a quadratic equation.
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