$$(x+4)^2 = 15$$
Answer
$$ \begin{matrix}x_1 = -4-\sqrt{ 15 } & x_2 = -4+\sqrt{ 15 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x+4)^2 &= 15&& \text{simplify left side} \\[1 em]x^2+8x+16 &= 15&& \text{move all terms to the left hand side } \\[1 em]x^2+8x+16-15 &= 0&& \text{simplify left side} \\[1 em]x^2+8x+1 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+8x+1 = 0 $ is a quadratic equation.
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