$$\frac{x+4}{x^4+4x^2} = 0$$
Answer
$$ x = -4 $$
Explanation
$$ \begin{aligned} \frac{x+4}{x^4+4x^2} &= 0&& \text{multiply ALL terms by } \color{blue}{ x^4+4x^2 }. \\[1 em](x^4+4x^2)\frac{x+4}{x^4+4x^2} &= (x^4+4x^2)\cdot0&& \text{cancel out the denominators} \\[1 em]x+4 &= 0&& \text{ move the constants to the right } \\[1 em]x &= -4&& \\[1 em]x &= -4&& \\[1 em] \end{aligned} $$
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