$$(x+3)(x+2) = (x-1)(x+4)$$

$$ \begin{aligned} (x+3)(x+2) &= (x-1)(x+4)&& \text{simplify left and right hand side} \\[1 em]x^2+2x+3x+6 &= x^2+4x-x-4&& \\[1 em]x^2+5x+6 &= x^2+3x-4&& \text{move all terms to the left hand side } \\[1 em]x^2+5x+6-x^2-3x+4 &= 0&& \text{simplify left side} \\[1 em]x^2+5x+6-x^2-3x+4 &= 0&& \\[1 em]2x+10 &= 0&& \text{ move the constants to the right } \\[1 em]2x &= -10&& \text{ divide both sides by $ 2 $ } \\[1 em]x &= -\frac{10}{2}&& \\[1 em]x &= -5&& \\[1 em] \end{aligned} $$

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