$$(x+3)(x-6) = 22$$
Answer
$$ \begin{matrix}x_1 = -5 & x_2 = 8 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x+3)(x-6) &= 22&& \text{simplify left side} \\[1 em]x^2-6x+3x-18 &= 22&& \\[1 em]x^2-3x-18 &= 22&& \text{move all terms to the left hand side } \\[1 em]x^2-3x-18-22 &= 0&& \text{simplify left side} \\[1 em]x^2-3x-40 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-3x-40 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Equations Solver