$$(x+2)\frac{x-2}{x+1} = 0$$
Answer
$$ \begin{matrix}x_1 = 2 & x_2 = -2 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x+2)\frac{x-2}{x+1} &= 0&& \text{simplify left side} \\[1 em]\frac{x^2-4}{x+1} &= 0&& \text{multiply ALL terms by } \color{blue}{ x+1 }. \\[1 em](x+1)\frac{x^2-4}{x+1} &= (x+1)\cdot0&& \text{cancel out the denominators} \\[1 em]x^2-4 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-4 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Equations Solver