$$(x+1)(x^3-8x^2+21x+14) = 0$$
Answer
$$ \begin{matrix}x_1 = -1 & x_2 = -0.54555 & x_3 = 4.27278+2.72129i \\[1 em] x_4 = 4.27278-2.72129i & \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x+1)(x^3-8x^2+21x+14) &= 0&& \text{simplify left side} \\[1 em]x^4-7x^3+13x^2+35x+14 &= 0&& \\[1 em] \end{aligned} $$
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