$$(x-7)^2 = 81$$
Answer
$$ \begin{matrix}x_1 = -2 & x_2 = 16 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-7)^2 &= 81&& \text{simplify left side} \\[1 em]x^2-14x+49 &= 81&& \text{move all terms to the left hand side } \\[1 em]x^2-14x+49-81 &= 0&& \text{simplify left side} \\[1 em]x^2-14x-32 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-14x-32 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Equations Solver