$$(x-4)(2x+3) = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 3 }{ 2 } & x_2 = 4 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-4)(2x+3) &= 0&& \text{simplify left side} \\[1 em]2x^2+3x-8x-12 &= 0&& \\[1 em]2x^2-5x-12 &= 0&& \\[1 em] \end{aligned} $$
$ 2x^{2}-5x-12 = 0 $ is a quadratic equation.
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