$$(x-3)^2 = 7$$
Answer
$$ \begin{matrix}x_1 = 3-\sqrt{ 7 } & x_2 = 3+\sqrt{ 7 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-3)^2 &= 7&& \text{simplify left side} \\[1 em]x^2-6x+9 &= 7&& \text{move all terms to the left hand side } \\[1 em]x^2-6x+9-7 &= 0&& \text{simplify left side} \\[1 em]x^2-6x+2 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-6x+2 = 0 $ is a quadratic equation.
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