$$(x-3)(x+5) = 9$$
Answer
$$ \begin{matrix}x_1 = 4 & x_2 = -6 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-3)(x+5) &= 9&& \text{simplify left side} \\[1 em]x^2+5x-3x-15 &= 9&& \\[1 em]x^2+2x-15 &= 9&& \text{move all terms to the left hand side } \\[1 em]x^2+2x-15-9 &= 0&& \text{simplify left side} \\[1 em]x^2+2x-24 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+2x-24 = 0 $ is a quadratic equation.
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