$$(x-3)(x+2) = 0$$
Answer
$$ \begin{matrix}x_1 = -2 & x_2 = 3 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-3)(x+2) &= 0&& \text{simplify left side} \\[1 em]x^2+2x-3x-6 &= 0&& \\[1 em]x^2-x-6 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-x-6 = 0 $ is a quadratic equation.
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