$$(x-2)(x+9) = 0$$
Answer
$$ \begin{matrix}x_1 = 2 & x_2 = -9 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (x-2)(x+9) &= 0&& \text{simplify left side} \\[1 em]x^2+9x-2x-18 &= 0&& \\[1 em]x^2+7x-18 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+7x-18 = 0 $ is a quadratic equation.
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