$$\frac{x^2-9}{x+3} = 0$$
Answer
$$ \begin{matrix}x_1 = 3 & x_2 = -3 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} \frac{x^2-9}{x+3} &= 0&& \text{multiply ALL terms by } \color{blue}{ x+3 }. \\[1 em](x+3)\frac{x^2-9}{x+3} &= (x+3)\cdot0&& \text{cancel out the denominators} \\[1 em]x^2-9 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-9 = 0 $ is a quadratic equation.
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