$$\frac{x^2-15x+54}{x-6} = 0$$
Answer
$$ \begin{matrix}x_1 = 6 & x_2 = 9 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} \frac{x^2-15x+54}{x-6} &= 0&& \text{multiply ALL terms by } \color{blue}{ x-6 }. \\[1 em](x-6)\frac{x^2-15x+54}{x-6} &= (x-6)\cdot0&& \text{cancel out the denominators} \\[1 em]x^2-15x+54 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}-15x+54 = 0 $ is a quadratic equation.
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