$$\frac{t-3}{2} = \frac{4-3t}{4}$$

$$ \begin{aligned} \frac{t-3}{2} &= \frac{4-3t}{4}&& \text{multiply ALL terms by } \color{blue}{ 4 }. \\[1 em]4 \cdot \frac{t-3}{2} &= 4 \cdot \frac{4-3t}{4}&& \text{cancel out the denominators} \\[1 em]2t-6 &= 4-3t&& \text{move the $ \color{blue}{ -3t } $ to the left side and $ \color{blue}{ -6 }$ to the right} \\[1 em]2t+3t &= 4+6&& \text{simplify left and right hand side} \\[1 em]5t &= 10&& \text{ divide both sides by $ 5 $ } \\[1 em]t &= \frac{10}{5}&& \\[1 em]t &= 2&& \\[1 em] \end{aligned} $$

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