$$(a+7)(a-5) = 0$$
Answer
$$ \begin{matrix}a_1 = 5 & a_2 = -7 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (a+7)(a-5) &= 0&& \text{simplify left side} \\[1 em]a^2-5a+7a-35 &= 0&& \\[1 em]a^2+2a-35 &= 0&& \\[1 em] \end{aligned} $$
$ x^{2}+2x-35 = 0 $ is a quadratic equation.
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