$$(9x-5)(2x+3) = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 3 }{ 2 } & x_2 = \dfrac{ 5 }{ 9 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (9x-5)(2x+3) &= 0&& \text{simplify left side} \\[1 em]18x^2+27x-10x-15 &= 0&& \\[1 em]18x^2+17x-15 &= 0&& \\[1 em] \end{aligned} $$
$ 18x^{2}+17x-15 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Equations Solver