$$(6x-7)^2 = 9$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 2 }{ 3 } & x_2 = \dfrac{ 5 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (6x-7)^2 &= 9&& \text{simplify left side} \\[1 em]36x^2-84x+49 &= 9&& \text{move all terms to the left hand side } \\[1 em]36x^2-84x+49-9 &= 0&& \text{simplify left side} \\[1 em]36x^2-84x+40 &= 0&& \\[1 em] \end{aligned} $$
$ 36x^{2}-84x+40 = 0 $ is a quadratic equation.
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