$$\frac{6x^2+60x}{6x} = 0$$
Answer
$$ \begin{matrix}x_1 = 0 & x_2 = -10 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} \frac{6x^2+60x}{6x} &= 0&& \text{multiply ALL terms by } \color{blue}{ 6x }. \\[1 em]6x \cdot \frac{6x^2+60x}{6x} &= 6x\cdot0&& \text{cancel out the denominators} \\[1 em]6x^4+60x^3 &= 0&& \\[1 em] \end{aligned} $$
In order to solve $ \color{blue}{ 6x^{4}+60x^{3} = 0 } $, first we need to factor our $ x^3 $.
$$ 6x^{4}+60x^{3} = x^3 \left( 6x+60 \right) $$$ x = 0 $ is a root of multiplicity $ 3 $.
The second root can be found by solving equation $ 6x+60 = 0$.
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