$$6+3x\cdot4+18-\frac{12}{2} = 0$$

$$ \begin{aligned} 6+3x\cdot4+18-\frac{12}{2} &= 0&& \text{multiply ALL terms by } \color{blue}{ 2 }. \\[1 em]2\cdot6+23x\cdot4+2\cdot(18-\frac{12}{2}) &= 2\cdot0&& \text{cancel out the denominators} \\[1 em]12+24x+24 &= 0&& \text{simplify left side} \\[1 em]24x+36 &= 0&& \text{ move the constants to the right } \\[1 em]24x &= -36&& \text{ divide both sides by $ 24 $ } \\[1 em]x &= -\frac{36}{24}&& \\[1 em]x &= -\frac{3}{2}&& \\[1 em] \end{aligned} $$

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