$$(5x-2)(3x+4) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 2 }{ 5 } & x_2 = -\dfrac{ 4 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (5x-2)(3x+4) &= 0&& \text{simplify left side} \\[1 em]15x^2+20x-6x-8 &= 0&& \\[1 em]15x^2+14x-8 &= 0&& \\[1 em] \end{aligned} $$
$ 15x^{2}+14x-8 = 0 $ is a quadratic equation.
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