$$\frac{5-r}{4} = \frac{1}{r}$$
Answer
$$ \begin{matrix}r_1 = 1 & r_2 = 4 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} \frac{5-r}{4} &= \frac{1}{r}&& \text{multiply ALL terms by } \color{blue}{ 4r }. \\[1 em]4r\frac{5-r}{4} &= 4r\cdot\frac{1}{r}&& \text{cancel out the denominators} \\[1 em]-r^2+5r &= 4&& \text{move all terms to the left hand side } \\[1 em]-r^2+5r-4 &= 0&& \\[1 em] \end{aligned} $$
$ -x^{2}+5x-4 = 0 $ is a quadratic equation.
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