$$(5-\frac{12}{2})(4-6)^2 = 0$$
Answer
This equation has no solution.
Explanation
$$ \begin{aligned} (5-\frac{12}{2})(4-6)^2 &= 0&& \text{simplify left side} \\[1 em](5-\frac{12}{2})\cdot(-2)^2 &= 0&& \\[1 em](5-\frac{12}{2})\cdot4 &= 0&& \\[1 em]-1\cdot4 &= 0&& \\[1 em]-4 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ -4 = 0 } $ is FALSE, we conclude that the equation has no solution.
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