$$(4x+2)(x+1) = 0$$
Answer
$$ \begin{matrix}x_1 = -1 & x_2 = -\dfrac{ 1 }{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (4x+2)(x+1) &= 0&& \text{simplify left side} \\[1 em]4x^2+4x+2x+2 &= 0&& \\[1 em]4x^2+6x+2 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}+6x+2 = 0 $ is a quadratic equation.
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