$$(4x+4)(2x-1) = 0$$
Answer
$$ \begin{matrix}x_1 = -1 & x_2 = \dfrac{ 1 }{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (4x+4)(2x-1) &= 0&& \text{simplify left side} \\[1 em]8x^2-4x+8x-4 &= 0&& \\[1 em]8x^2+4x-4 &= 0&& \\[1 em] \end{aligned} $$
$ 8x^{2}+4x-4 = 0 $ is a quadratic equation.
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