$\frac{4 x ^{2} - 2 x + 1}{2 x + 3} = 0$

Answer

$x_{1} = \frac{1}{4} + \frac{3}{4} i x_{2} = \frac{1}{4} - \frac{3}{4} i$

Explanation

\frac{4 x ^{2} - 2 x + 1}{2 x + 3} (2 x + 3) \frac{4 x ^{2} - 2 x + 1}{2 x + 3} 4 x^{2} - 2 x + 1 = 0 = (2 x + 3) \cdot 0 = 0 multiply ALL terms by 2 x + 3 . cancel out the denominators

$4 x^{2} - 2 x + 1 = 0$ is a quadratic equation.

You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.

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$\frac{4 x ^{2} - 2 x + 1}{2 x + 3} = 0$

$x_{1} = \frac{1}{4} + \frac{3}{4} i x_{2} = \frac{1}{4} - \frac{3}{4} i$