$$\frac{4+x}{x+2} = 1$$

$$ \begin{aligned} \frac{4+x}{x+2} &= 1&& \text{multiply ALL terms by } \color{blue}{ x+2 }. \\[1 em](x+2)\frac{4+x}{x+2} &= (x+2)\cdot1&& \text{cancel out the denominators} \\[1 em]4+x &= x+2&& \text{move the $ \color{blue}{ x } $ to the left side and $ \color{blue}{ 4 }$ to the right} \\[1 em]x-x &= 2-4&& \text{simplify left and right hand side} \\[1 em]x-x &= -2&& \\[1 em]0 &= -2&& \\[1 em] \end{aligned} $$

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