$$ \begin{aligned} (4+3)\cdot2-\frac{10}{2} &= 0&& \text{multiply ALL terms by } \color{blue}{ 2 }. \\[1 em]2(4+3)\cdot2-2\cdot\frac{10}{2} &= 2\cdot0&& \text{cancel out the denominators} \\[1 em]28-10 &= 0&& \text{simplify left side} \\[1 em]18 &= 0&& \\[1 em] \end{aligned} $$
Since the statement $ \color{red}{ 18 = 0 } $ is FALSE, we conclude that the equation has no solution.
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