$$\frac{4h}{3+h-3} = 0$$
Answer
$$ h = 0 $$
Explanation
$$ \begin{aligned} \frac{4h}{3+h-3} &= 0&& \text{multiply ALL terms by } \color{blue}{ 3+h-3 }. \\[1 em](3+h-3)\frac{4h}{3+h-3} &= (3+h-3)\cdot0&& \text{cancel out the denominators} \\[1 em]4h &= 0&& \text{ divide both sides by $ 4 $ } \\[1 em]h &= \frac{0}{4}&& \\[1 em]h &= 0&& \\[1 em] \end{aligned} $$
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