$$(4-5x)(5x^3+6x^2-3x+5) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 4 }{ 5 } & x_2 = -1.82766 & x_3 = 0.31383+0.66982i \\[1 em] x_4 = 0.31383-0.66982i & \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (4-5x)(5x^3+6x^2-3x+5) &= 0&& \text{simplify left side} \\[1 em]-25x^4-10x^3+39x^2-37x+20 &= 0&& \\[1 em] \end{aligned} $$
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