$$(3x+2)(x+5) = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 2 }{ 3 } & x_2 = -5 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (3x+2)(x+5) &= 0&& \text{simplify left side} \\[1 em]3x^2+15x+2x+10 &= 0&& \\[1 em]3x^2+17x+10 &= 0&& \\[1 em] \end{aligned} $$
$ 3x^{2}+17x+10 = 0 $ is a quadratic equation.
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