$$(2x-5)(4x+3) = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 3 }{ 4 } & x_2 = \dfrac{ 5 }{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (2x-5)(4x+3) &= 0&& \text{simplify left side} \\[1 em]8x^2+6x-20x-15 &= 0&& \\[1 em]8x^2-14x-15 &= 0&& \\[1 em] \end{aligned} $$
$ 8x^{2}-14x-15 = 0 $ is a quadratic equation.
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