$$(2x-5)(3x+4) = 0$$
Answer
$$ \begin{matrix}x_1 = -\dfrac{ 4 }{ 3 } & x_2 = \dfrac{ 5 }{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (2x-5)(3x+4) &= 0&& \text{simplify left side} \\[1 em]6x^2+8x-15x-20 &= 0&& \\[1 em]6x^2-7x-20 &= 0&& \\[1 em] \end{aligned} $$
$ 6x^{2}-7x-20 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Equations Solver