$$(2x-4)^2 = 1$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 3 }{ 2 } & x_2 = \dfrac{ 5 }{ 2 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (2x-4)^2 &= 1&& \text{simplify left side} \\[1 em]4x^2-16x+16 &= 1&& \text{move all terms to the left hand side } \\[1 em]4x^2-16x+16-1 &= 0&& \text{simplify left side} \\[1 em]4x^2-16x+15 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}-16x+15 = 0 $ is a quadratic equation.
You can use step-by-step quadratic equation solver to see a detailed explanation on how to solve this equation.
This page was created using
Equations Solver