$$(2x-10)(2x-8) = 0$$
Answer
$$ \begin{matrix}x_1 = 4 & x_2 = 5 \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (2x-10)(2x-8) &= 0&& \text{simplify left side} \\[1 em]4x^2-16x-20x+80 &= 0&& \\[1 em]4x^2-36x+80 &= 0&& \\[1 em] \end{aligned} $$
$ 4x^{2}-36x+80 = 0 $ is a quadratic equation.
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