$$(2x-1)(5x+3) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 1 }{ 2 } & x_2 = -\dfrac{ 3 }{ 5 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (2x-1)(5x+3) &= 0&& \text{simplify left side} \\[1 em]10x^2+6x-5x-3 &= 0&& \\[1 em]10x^2+x-3 &= 0&& \\[1 em] \end{aligned} $$
$ 10x^{2}+x-3 = 0 $ is a quadratic equation.
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