Question
$$(2+3x)\cdot(2-3x) = 0$$
Answer
$$ \begin{matrix}x_1 = \dfrac{ 2 }{ 3 } & x_2 = -\dfrac{ 2 }{ 3 } \\[1 em] \end{matrix} $$
Explanation
$$ \begin{aligned} (2+3x)\cdot(2-3x) &= 0&& \text{simplify left side} \\[1 em]4-6x+6x-9x^2 &= 0&& \\[1 em]4-6x+6x-9x^2 &= 0&& \\[1 em]-9x^2+4 &= 0&& \\[1 em] \end{aligned} $$
$ -9x^{2}+4 = 0 $ is a quadratic equation.
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